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ai: turn inline latex into latex code blocks for proper rendering

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it looks poopy sometimes but still better than copilot failing all the time
This commit is contained in:
end-4
2025-04-03 23:19:13 +02:00
parent ac59f23ca4
commit 5591e59680
2 changed files with 22 additions and 5 deletions
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.config/ags/modules/.miscutils/md2pango.js
+18
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@@ -4,6 +4,7 @@
const monospaceFonts = 'JetBrains Mono NF, JetBrains Mono Nerd Font, JetBrains Mono NL, SpaceMono NF, SpaceMono Nerd Font, monospace';
const codeBlockRegex = /^\s*```([a-zA-Z0-9]+)?\n?/;
const replacements = {
'indents': [
{ name: 'BULLET', re: /^(\s*)([\*\-]\s)(.*)(\s*)$/, sub: ' $1- $3' },
@@ -31,6 +32,11 @@ const replacements = {
{ name: 'INLCODE', re: /(`)([^`]*)(`)/g, sub: '<span font_weight="bold" font_family="' + monospaceFonts + '">$2</span>' },
// { name: 'UND', re: /(__|\*\*)(\S[\s\S]*?\S)(__|\*\*)/g, sub: "<u>$2</u>" },
],
'forceLatex': [
{ name: 'LATEX_INLINE_SQUARE', re: /\\\[(.*?)\\\]/g, sub: '\n```latex\n$1\n```' },
{ name: 'LATEX_INLINE_ROUND', re: /\\\((.*?)\\\)/g, sub: '\n```latex\n$1\n```' },
{ name: 'LATEX_INLINE_DOLLAR', re: /\$(.*?)\$/g, sub: '\n```latex\n$1\n```' }
]
}
const replaceCategory = (text, replaces) => {
@@ -42,12 +48,22 @@ const replaceCategory = (text, replaces) => {
// Main function
export function replaceInlineLatexWithCodeBlocks(text) {
return text.replace(/\\\[(.*?)\\\]|\\\((.*?)\\\)|\$(.*?)\$/gs, (match, square, round, dollar) => {
const latex = square || round || dollar;
return `\n\`\`\`latex\n${latex}\n\`\`\`\n`;
});
}
export default (text) => {
let lines = text.split('\n')
let output = [];
let inCode = false;
// Replace
for (const line of lines) {
let result = line;
if (codeBlockRegex.test(line)) inCode = !inCode;
if (inCode) continue;
result = replaceCategory(result, replacements.indents);
result = replaceCategory(result, replacements.escapes);
result = replaceCategory(result, replacements.sections);
@@ -74,6 +90,8 @@ int main(int argc, char* argv[]) {
}
\`\`\`
## LaTeX
- Inline LaTeX: \\[ \\frac{d}{dx} \\left( \\frac{x-438}{x^2+23x-7} \\right) = \\frac{-x^2 + 869}{(x^2+23x-7)^2} \\]
- Block LaTeX:
\`\`\`latex
\\frac{d}{dx} \\left( \\frac{x-438}{x^2+23x-7} \\right) = \\frac{-x^2 + 869}{(x^2+23x-7)^2} \\\\ → \\\\ cos(2x) = 2cos^2(x) - 1 = 1 - 2sin^2(x) = cos^2(x) - sin^2(x)
\`\`\`